(((1+i))/((1-i)))^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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đối xứng 9−x²

Solution

x=0

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Trục Đối xứng

Đối với một parabol ở dạng chuẩn y=ax²+bx+c ttrục đối xứng là đường thẳng đứng đi qua đỉnh x=−b2a

Trục đối xứng cho y=ax²+bx+c là x=−b2a
a=−1, b=0

x=−02(−1)

Tinh chỉnh

x=0

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(((1+i))/((1-i)))^2

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