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sequence type a_{n}=3n+2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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quy tắc tích ddx ((2−3x)(x²+5x−1))

Solution

−9x²−26x+13

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ddx ((2−3x)(x²+5x−1))

Áp dụng Quy tắc Nhân: (f·g)′=f ′·g+f·g′

f=2−3x, g=x²+5x−1

=ddx (2−3x)(x²+5x−1)+ddx (x²+5x−1)(2−3x)

ddx (2−3x)=−3

ddx (x²+5x−1)=2x+5

=(−3)(x²+5x−1)+(2x+5)(2−3x)

Rút gọn (−3)(x²+5x−1)+(2x+5)(2−3x): −9x²−26x+13

=−9x²−26x+13

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sequence type a_{n}=3n+2

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