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tiêu điểm f(x)=(2x^2-6x)+(-2x^2+5x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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các hệ số chặn (x²+2x−1)· (2x²−3x+6)

Solution

hệ số chặn X: (−1+√2, 0), (−1−√2, 0), hệ số chặn Y: (0, −6)

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(x−1)²9 +y²5 =100

Phương trình chuẩn hình elip

(x−h)²a² +(y−k)²b² =1 là phương trình chuẩn hình elip
với tâm (h, k) và a, b là bán trục chính và bán trục phụ

Viết lại (x−1)²9 +y²5 =100 dưới dạng phương trình hình elip chuẩn

(x−1)²30² +(y−0)²(10√5)² =1

Do đó các thuộc tính của ellipse là:

(h, k)=(1, 0), a=30, b=10√5

a>b do đó a là bán trục chính và b là bán trục nhỏ

Hình elip có tâm (h, k)=(1, 0), a=30, b=10√5

Và tâm là:

(1, 0)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

tiêu điểm f(x)=(2x^2-6x)+(-2x^2+5x)

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