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points of on same line (2, 96), (3, 144), (4, 192)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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hội tụ tuyệt đối ∑_n=1^∞(−1)ⁿsin(n)n²

Solution

hội tụ (hoàn toàn)

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∑_n=1^∞(−1)ⁿsin(n)n²

Chuỗi có các phần tử dương và âm, hãy kiểm tra sự hội tụ có điều kiện/tuyệt đối

Định nghĩa hội tụ tuyệt đối/có điều kiện

Hội tụ tuyệt đối: ∑a_n hoàn toàn hội tụ nếu ∑|a_n| là hội tụ
Hội tụ có điều kiện: ∑a_n là hội tụ có điều kiện nếu ∑|a_n| là phân kỳ và ∑a_n là hội tụ

Kiểm tra sự hội tụ của ∑_n=1^∞|(−1)ⁿsin(n)n² |: hội tụ

=hội tụ (hoàn toàn)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

points of on same line (2, 96), (3, 144), (4, 192)

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