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((-2)^3+(-1)^2)^2-2+5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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|3x+2||x−1| >2

Solution

x<−4 or 0<x<1 or x>1

Interval Notation

(−∞ , −4)∪(0, 1)∪(1, ∞ )

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Solution steps

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Điểm cuối cho trước điểm đầu (x₁, y₁) và trung điểm (x₂, y₂): (2x₂−x₁, 2y₂−y₁)

(x₁, y₁)=(−9, 4), (x₂, y₂)=(−132 , 6)

=(2(−132 )−(−9), 2· 6−4)

Rút gọn

=(−4, 8)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

((-2)^3+(-1)^2)^2-2+5

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