convert 5 h to s

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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phép trừ số lớn 67−14

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(7x−9)²

Áp dụng công thức bình phương hoàn hảo: (a−b)²=a²−2ab+b²

(7x−9)²=(7x)²−2· 7x· 9+9²

=(7x)²−2· 7x· 9+9²

Rút gọn (7x)²−2· 7x· 9+9²: 49x²−126x+81

=49x²−126x+81

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CHÀO, hỏi một câu hỏi về phép trừ số lớn 67−14 hoặc chọn bên dưới

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

convert 5 h to s

Solution

Solution steps

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