phạm vi cos(2x+5)

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nghịch đảo x(x−1)²x²−1

Solution

1+x+√x²+6x+12 , 1+x−√x²+6x+12

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Solution steps

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Định nghĩa nghịch đảo hàm

Một hàm g là nghịch đảo của hàm f nếu cho y=f(x), x=g(y)

y=x(x−1)²x²−1

Thay thế x bằng y

x=y(y−1)²y²−1

Giải y, x=y(y−1)²y²−1

1+x+√x²+6x+12 , 1+x−√x²+6x+12

Solve instead

miền x(x−1)²x²−1

phạm vi x(x−1)²x²−1

các hệ số chặn x(x−1)²x²−1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

phạm vi cos(2x+5)

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