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integral of (sqrt(x-4)-3)/(x-13)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ddh ((6h+1)−(9h+4))

Solution

−3

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ddh ((6h+1)−(9h+4))

Rút gọn (6h+1)−(9h+4): −3h−3

=ddh (−3h−3)

Áp dụng quy tắc Đạo hàm của một Tổng: (f±g)′=f ′±g′

=−ddh (3h)−ddh (3)

ddh (3h)=3

ddh (3)=0

=−3−0

Rút gọn

=−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of (sqrt(x-4)-3)/(x-13)

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