tiêu điểm y=3x*x

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biến đổi laplace cos²(θ)

Solution

12s +s2(s²+4)

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L{cos²(θ)}

Sử dụng hằng đẳng thức sau: cos²(x)=12 +cos(2x)12

=L{12 +cos(2θ)12 }

Sử dụng thuộc tính tuyến tính của Biến đổi Laplace:
Đối với các hàm f(t), g(t) và hằng số a, b: L{a·f(t)+b·g(t)}=a·L{f(t)}+b·L{g(t)}

=L{12 }+12 L{cos(2θ)}

L{12 }: 12s

L{cos(2θ)}: ss²+4

=12s +12 · ss²+4

Tinh chỉnh 12s +12 · ss²+4 : 12s +s2(s²+4)

=12s +s2(s²+4)

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laplace ngược cos²(θ)

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Giải quyết thay thế laplace ngược cos²(θ)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

tiêu điểm y=3x*x

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