phạm vi sqrt(x+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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2x³yy^′+3x²y²+7=0

Solution

y=√−7x+c₁x√x , y=−√−7x+c₁x√x

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Định nghĩa dịch chuyển

Đối với f(x)=A·g (Bx−C)+D, trong đó g(x) ilà một trong những hàm lượng giác cơ bản,
CB là lệch pha
D dịch chuyển đứng

f(x)=2cos(2x−1)+4
g (Bx−C)=cos(2x−1), B=2, C=1, D=4
Do đó, sự dịch chuyển giai đoạn CB là 12

Dịch chuyển dọc D là 4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

phạm vi sqrt(x+1)

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