miền cos(2x+5)

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∫ sin²(u)du

Solution

12 (u−12 sin(2u))+C

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∫ sin²(u)du

Viết lại bằng cách sử dụng hằng đẳng thức lượng giác

=∫ 1−cos(2u)2 du

Đưa hằng số ra ngoài: ∫a·f(x)dx=a·∫f(x)dx

=12 · ∫ 1−cos(2u)du

Áp dụng quy tắc tổng: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=12 (∫ 1du−∫ cos(2u)du)

∫ 1du=u

∫ cos(2u)du=12 sin(2u)

=12 (u−12 sin(2u))

Thêm một hằng số vào Lời giải

=12 (u−12 sin(2u))+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

miền cos(2x+5)

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