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Phổ biến Word Problems >

Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

Lời Giải

Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

Lời Giải

The numbers : 9, 10 or - 2, - 1

Các bước giải pháp

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

(x + 1)^{2} = 19 + 9 x

Giải

(x + 1)^{2} = 19 + 9 x : x = 9, x = - 2

Thay

x = 9 : 10

Thay

x = - 2 : - 1

The numbers : 9, 10 or - 2, - 1

Ví dụ phổ biến

The sum of two numbers is 45 . One number is 4 times as large as the other. What are the numbers?Two sevenths of a number is 30 less than the number. Find the number If 5 times a number is decreased by 12 , the result is 108 . What is the number?The sum of four times a number and 11 is 37. Find the number.For two consecutive integers, the sum of the smaller and twice the larger is 29. Find the smaller integer.