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Phổ biến Word Problems >

David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Lời Giải

David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Lời Giải

David^{'} s age is : 20

Joaquin^{'} s age is : 16

Các bước giải pháp

Translate the problem into an equation:

x + x - 4 = 36

Giải

x, x + x - 4 = 36 : x = 20

Tìm age

David^{'} s age is : 20

Joaquin^{'} s age is : 16

Ví dụ phổ biến

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